Summarize this article:
Last updated on September 26, 2025
We use the derivative of 6e^x, which is 6e^x, to measure how the function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of 6e^x in detail.
We now understand the derivative of 6ex. It is commonly represented as d/dx (6ex) or (6ex)', and its value is 6ex.
The function 6ex has a clearly defined derivative, indicating it is differentiable over all real numbers. The key concepts are mentioned below:
Exponential Function: ex is the base of natural logarithms and has unique properties.
Constant Multiplication Rule: Rule for differentiating functions with constant coefficients.
Exponential Rule: This rule applies to derivatives of exponential functions.
The derivative of 6ex can be denoted as d/dx (6ex) or (6ex)'.
The formula we use to differentiate 6ex is: d/dx (6ex) = 6ex (or) (6ex)' = 6ex This formula applies to all x.
We can derive the derivative of 6ex using the standard rules of differentiation. To show this, we will use the exponential rule along with constant multiplication. There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of 6ex results in 6ex using the above-mentioned methods:
The derivative of 6ex can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of 6ex using the first principle, we will consider f(x) = 6ex. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = 6ex, we write f(x + h) = 6e(x + h). Substituting these into equation (1), f'(x) = limₕ→₀ [6e(x + h) - 6ex] / h = limₕ→₀ [6ex(eh - 1)] / h = 6ex limₕ→₀ [eh - 1] / h Using the fact that limₕ→₀ [eh - 1] / h = 1, we have, f'(x) = 6ex Hence, proved.
To prove the differentiation of 6ex using the exponential rule, We use the formula: d/dx (ex) = ex By the constant multiplication rule, d/dx (6ex) = 6 d/dx (ex) = 6ex Hence, proved.
We will now prove the derivative of 6ex using the chain rule. The step-by-step process is demonstrated below: Here, we use the formula, d/dx (6ex) = 6 d/dx (ex) Given that, u = x and v = ex Using the chain rule formula: d/dx [u.v] = u'. v + u. v' u' = d/dx x = 1 (substitute u = x) v' = d/dx (e^x) = ex Using the chain rule, d/dx (6e^x) = 6 (1 * e^x) = 6ex Thus, proved.
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like 6ex.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point.
The second derivative is derived from the first derivative, which is denoted using f′′ (x) Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.
For the nth Derivative of 6ex, we generally use f n(x) for the nth derivative of a function f(x) which tells us the change in the rate of change (continuing for higher-order derivatives).
The derivative of 6ex is always defined, and there are no points where it becomes undefined. At x = 0, the derivative of 6ex = 6e0, which is 6.
Students frequently make mistakes when differentiating 6ex. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (6e^x·x^2)
Here, we have f(x) = 6ex·x². Using the product rule, f'(x) = u′v + uv′ In the given equation, u = 6e^x and v = x². Let’s differentiate each term, u′ = d/dx (6ex) = 6e^x v′ = d/dx (x²) = 2x substituting into the given equation, f'(x) = (6e^x)(x²) + (6e^x)(2x) Let’s simplify terms to get the final answer, f'(x) = 6e^x(x² + 2x) Thus, the derivative of the specified function is 6e^x(x² + 2x).
We find the derivative of the given function by dividing the function into two parts.
The first step is finding its derivative and then combining them using the product rule to get the final result.
A bacteria culture grows exponentially according to the function N(t) = 6e^t, where N is the number of bacteria at time t. Find the rate of growth of the bacteria culture at t = 2 hours.
We have N(t) = 6e^t (growth of the bacteria culture)...(1) Now, we will differentiate the equation (1) Take the derivative of 6e^t: dN/dt = 6e^t Given t = 2 (substitute this into the derivative) dN/dt |_(t=2) = 6e^2 Hence, the rate of growth of the bacteria culture at t = 2 hours is 6e^2.
We find the rate of growth of the bacteria culture at t = 2 hours by differentiating the exponential growth function and substituting the given value of t.
Derive the second derivative of the function y = 6e^x.
The first step is to find the first derivative, dy/dx = 6e^x...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [6e^x] Since the derivative of 6e^x with respect to x is 6e^x, d²y/dx² = 6e^x Therefore, the second derivative of the function y = 6e^x is 6e^x.
We use the step-by-step process, where we start with the first derivative.
The second derivative of an exponential function like 6e^x remains the same as the first due to the properties of exponential functions.
Prove: d/dx (6e^(2x)) = 12e^(2x).
Let’s start using the chain rule: Consider y = 6e^(2x) To differentiate, we use the chain rule: dy/dx = 6 * d/dx [e^(2x)] Since the derivative of e^(2x) is 2e^(2x), dy/dx = 6 * 2e^(2x) dy/dx = 12e^(2x) Hence proved.
In this step-by-step process, we used the chain rule to differentiate the function.
We replace the function with its derivative, multiply by the constant, and simplify to prove the equation.
Solve: d/dx (6e^x/x)
To differentiate the function, we use the quotient rule: d/dx (6e^x/x) = (d/dx (6e^x) * x - 6e^x * d/dx(x)) / x² We will substitute d/dx (6e^x) = 6e^x and d/dx (x) = 1 = (6e^x * x - 6e^x) / x² = (6xe^x - 6e^x) / x² Therefore, d/dx (6e^x/x) = (6xe^x - 6e^x) / x²
In this process, we differentiate the given function using the quotient rule.
As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.